4.9x^2-18x-50=0

Solution for 4.9x^2-18x-50=0 equation:

4.9x^2-18x-50=0

a = 4.9; b = -18; c = -50;
Δ = b2-4ac
Δ = -182-4·4.9·(-50)
Δ = 1304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1304}=\sqrt{4*326}=\sqrt{4}*\sqrt{326}=2\sqrt{326}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{326}}{2*4.9}=\frac{18-2\sqrt{326}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{326}}{2*4.9}=\frac{18+2\sqrt{326}}{9.8}
$